Sample problems

forked from scresawn's block: Sample problems: objects and arrays

forked from eamonm95's block: Sample problems

<!DOCTYPE html>
<head>
  <meta charset="utf-8">
  <script src="https://d3js.org/d3.v4.min.js"></script>
  <style>
    body { margin:0;position:fixed;top:0;right:0;bottom:0;left:0; }
  </style>
</head>

<body>
  <h1>Please look in the code below for 5 JavaScript practice problems.</h1>
  <p>(These problems don't include any SVG manipulation, so you will need to open the developer console in order to see the output of your code)</p>
  <script>
  // Problem 1: modify array1 so that each object it contains includes the 2 letter state "id"

array1 = [
    				{name: "Arizona",  location: "Southwest"},
           	{name: "Virginia", location: "East"},
            {name: "Florida",  location: "Southeast"}
           ];
    
  array2 = [
            {name: "Virginia", id: "VA"},
    				{name: "Arizona", id: "AZ"},
            {name: "Florida", id: "FL"}
  				 ];
	
  console.log("solution for problem 1:")
  array1.forEach(function(a1) {
    array2.forEach(function(a2) {
      if (a1.name == a2.name) {
        a1.id = a2.id        
      }
  	})
  })
  console.log(array1)
  // Problem 2: print all items that are in both array3 
  // and array4 to the console.
  
  array3 = ['a','b','c','d'];
  array4 = ['a','c','e','f','g'];
  
	console.log("solution for problem 2:")
  array3.forEach(function (a3) {
    array4.forEach(function (a4) {
      if (a3 == a4) {
        console.log(a3)
      }
    })
  })
  
  // console.log("second solution:")
  array3.forEach(function (a3) {
    if (array4.includes(a3)) {
        //console.log(a3);
        }
  })
  
  // Problem 3: 'states' is an array of objects. Sort the array in ascending order by population
  
  states = [{name: "Alaska", id: "AK", population: 741894},
            {name: "Virginia", id: "VA", population: 8411808},
    				{name: "Arizona", id: "AZ", population: 6931071},
            {name: "Florida", id: "FL", population: 20984400}]
	console.log("solution for problem 3:")
  states.sort(function(a, b){return a.population - b.population});
  console.log(states)
  
           
  // Problem 4: using console.log() and the appropriate index on the sorted 'states' array, print the state with the smallest population.
  console.log("solution for problem 4:")
  console.log(states[0]);
  
  // someNumbers is an array containing all integers from 1-10 inclusively
  someNumbers = d3.range(1,11)
  
  // Problem 5: using console.log(), a loop,and the modulus operator, print those members of someNumbers that are NOT multiples of 3.
  	console.log("solution for problem 5:")

someNumbers.forEach(function(num){
    if (num%3 != 0){
      console.log(num)
    }
  })

</script>
</body>

https://d3js.org/d3.v4.min.js